- You need a calculator to complete this!
- For 1-4 we are asked to find angle measures--remember, that means we need to use the trig inverses on our calculator!
- For #2 (a and b), your challenge is to find all of the angle measures and side lengths...
- For a, I would use the Pythagorean Theorem to find the third side of the triangle; then, set up trig ratios and use trig inverses to find the remaining angle measures
- For b, you can find the third angle measure because you know the three angles must sum (add up to) 180 degrees; then, use 27.5 as your "theta" and try to set up trig ratios to find the missing two sides
- #3 is like two problems combined in one...try this...
- To find the height of the taller building, first focus on the "little" triangle with the 20 degree angle in it
- Set up a trig ratio to find the "opposite" side of this little triangle; and remember, you know the "adjacent" side is 60 ft.
- Then, focus on the "upside down triangle" with the 35 degree angle
- Again, set up a trig ratio to find the "opposite" side of this triangle; again, the "adjacent" side is 60 ft.
- What do we have to do with these two answers to find the total height of the taller building?
- For #4, set up a trig ratio and then use trig inverses to find the angle measure between the ladder and the ground (theta).
- Based on this answer, is the ladder safe? (Safe means our angle can be no greater than 75 degrees...)
- For #5, remember that when you draw your triangle, the angle of depression is "outside" your triangle (at the top). Use this information to find the angle at the top on the "inside" of the triangle (these two angles must add to 90).
- Then, set up a trig ratio to find the "opposite" side given the "adjacent" side (125 ft.)
- For #6, draw a triangle...
- You should be trying to find the "opposite" side (height of the building) given the "adjacent" side (65 m. from the base).
- For #7, remember that "due North" refers to the vertical side and "east" refers to the horizontal side...
- Label your triangle with the given info--you know the "opposite" and "adjacent" sides of the triangle (for the theta given)
- Set up a trig ratio and use trig inverses to solve.
Good luck :)
Tomorrow we'll look at our homework and answer any questions; then, we'll get to some group work/practice!
On Monday we'll wrap up this section, and then we'll have our first test (likely next Wednesday)! Woohoo!
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